(5/3)x^2+3x+1=0

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Solution for (5/3)x^2+3x+1=0 equation: 



(5/3)x^2+3x+1=0



Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/3)x^2+3x+1=0

We add all the numbers together, and all the variables

3x+(+5/3)x^2+1=0

We multiply all the terms by the denominator


3x*3)x^2+(+1*3)x^2+5=0

We add all the numbers together, and all the variables

3x*3)x^2+3x^2+5=0

Wy multiply elements

9x^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{18}=0$

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